5ln(3x/4)=2

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Solution for 5ln(3x/4)=2 equation: 


D( x )

(3*x)/4 <= 0

(3*x)/4 <= 0

(3*x)/4 <= 0

3/4*x+0 <= 0 // - 0

3/4*x <= 0 // : 3/4

x <= 0/3/4

x <= 0

x in (0:+oo)

5*ln((3*x)/4) = 2 // - 2

5*ln((3*x)/4)-2 = 0

5*ln((3*x)/4)-2 = 0 // + 2

5*ln((3*x)/4) = 2 // : 5

ln((3*x)/4) = 2/5

ln((3*x)/4) = ln(e^(2/5))

(3*x)/4 = e^(2/5)

(3*x)/4-e^(2/5) = 0

3/4*x-e^(2/5) = 0 // + e^(2/5)

3/4*x = e^(2/5) // : 3/4

x = (e^(2/5))/3/4

x = 4/3*e^(2/5)

x = 4/3*e^(2/5)

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