5k-3(2k2/3)-9=0

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Solution for 5k-3(2k2/3)-9=0 equation: 


k in (-oo:+oo)

5*k-(3*((2*k^2)/3))-9 = 0

5*k-2*k^2-9 = 0

5*k-2*k^2-9 = 0

DELTA = 5^2-(-9*(-2)*4)

DELTA = -47

DELTA < 0

k belongs to the empty set

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