5k+4(3-2k)=6(k-4)

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Solution for 5k+4(3-2k)=6(k-4) equation: 



5k+4(3-2k)=6(k-4)

We move all terms to the left:

5k+4(3-2k)-(6(k-4))=0

We add all the numbers together, and all the variables

5k+4(-2k+3)-(6(k-4))=0

We multiply parentheses

5k-8k-(6(k-4))+12=0



We calculate terms in parentheses: -(6(k-4)), so:

6(k-4)

We multiply parentheses

6k-24

Back to the equation:

-(6k-24)



We add all the numbers together, and all the variables

-3k-(6k-24)+12=0

We get rid of parentheses

-3k-6k+24+12=0

We add all the numbers together, and all the variables

-9k+36=0

We move all terms containing k to the left, all other terms to the right

-9k=-36

k=-36/-9

k=+4

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