5k+1/3(2k-4)=10

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Solution for 5k+1/3(2k-4)=10 equation: 



5k+1/3(2k-4)=10

We move all terms to the left:

5k+1/3(2k-4)-(10)=0



Domain of the equation: 3(2k-4)!=0

k∈R



We multiply all the terms by the denominator


5k*3(2k-4)-10*3(2k-4)+1=0

Wy multiply elements

15k^2(2-30k(2+1=0

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