5i+5(2+2i)=-35

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Solution for 5i+5(2+2i)=-35 equation: 



5i+5(2+2i)=-35

We move all terms to the left:

5i+5(2+2i)-(-35)=0

We add all the numbers together, and all the variables

5i+5(2i+2)-(-35)=0

We add all the numbers together, and all the variables

5i+5(2i+2)+35=0

We multiply parentheses

5i+10i+10+35=0

We add all the numbers together, and all the variables

15i+45=0

We move all terms containing i to the left, all other terms to the right

15i=-45

i=-45/15

i=-3

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