5i(8-3i)=0

Solution for 5i(8-3i)=0 equation:

5i(8-3i)=0

We add all the numbers together, and all the variables

5i(-3i+8)=0

We multiply parentheses

-15i^2+40i=0

a = -15; b = 40; c = 0;
Δ = b2-4ac
Δ = 402-4·(-15)·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40}{2*-15}=\frac{-80}{-30}
=2+2/3
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40}{2*-15}=\frac{0}{-30}
=0
$