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5g(8g+6)=40g+6
We move all terms to the left:
5g(8g+6)-(40g+6)=0
We multiply parentheses
40g^2+30g-(40g+6)=0
We get rid of parentheses
40g^2+30g-40g-6=0
We add all the numbers together, and all the variables
40g^2-10g-6=0
a = 40; b = -10; c = -6;
Δ = b2-4ac
Δ = -102-4·40·(-6)
Δ = 1060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1060}=\sqrt{4*265}=\sqrt{4}*\sqrt{265}=2\sqrt{265}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{265}}{2*40}=\frac{10-2\sqrt{265}}{80} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{265}}{2*40}=\frac{10+2\sqrt{265}}{80} $
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