5d+4-2d-10=3(d-2)

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Solution for 5d+4-2d-10=3(d-2) equation: 



5d+4-2d-10=3(d-2)

We move all terms to the left:

5d+4-2d-10-(3(d-2))=0

We add all the numbers together, and all the variables

3d-(3(d-2))-6=0



We calculate terms in parentheses: -(3(d-2)), so:

3(d-2)

We multiply parentheses

3d-6

Back to the equation:

-(3d-6)



We get rid of parentheses

3d-3d+6-6=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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