5d+2(2-1d)=3+(1+1d)+1

Solution for 5d+2(2-1d)=3+(1+1d)+1 equation:

5d+2(2-1d)=3+(1+1d)+1

We move all terms to the left:

5d+2(2-1d)-(3+(1+1d)+1)=0

We add all the numbers together, and all the variables

5d+2(-1d+2)-(3+(d+1)+1)=0

We multiply parentheses

5d-2d-(3+(d+1)+1)+4=0


We calculate terms in parentheses: -(3+(d+1)+1), so:

3+(d+1)+1

determiningTheFunctionDomain
(d+1)+3+1

We add all the numbers together, and all the variables

(d+1)+4

We get rid of parentheses

d+1+4

We add all the numbers together, and all the variables

d+5

Back to the equation:

-(d+5)


We add all the numbers together, and all the variables

3d-(d+5)+4=0

We get rid of parentheses

3d-d-5+4=0

We add all the numbers together, and all the variables

2d-1=0

We move all terms containing d to the left, all other terms to the right

2d=1

d=1/2

d=1/2