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5d+(2-d)=3(1+d+1
We move all terms to the left:
5d+(2-d)-(3(1+d+1)=0
We add all the numbers together, and all the variables
5d+(-1d+2)-(3(d+2)=0
We get rid of parentheses
5d-1d-(3(d+2)+2=0
We add all the numbers together, and all the variables
4d-(3(d+2)+2=0
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