5c=7(2c+3)-12

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Solution for 5c=7(2c+3)-12 equation: 



5c=7(2c+3)-12

We move all terms to the left:

5c-(7(2c+3)-12)=0



We calculate terms in parentheses: -(7(2c+3)-12), so:

7(2c+3)-12

We multiply parentheses

14c+21-12

We add all the numbers together, and all the variables

14c+9

Back to the equation:

-(14c+9)



We get rid of parentheses

5c-14c-9=0

We add all the numbers together, and all the variables

-9c-9=0

We move all terms containing c to the left, all other terms to the right

-9c=9

c=9/-9

c=-1

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