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5c+c-27=3(c+4)-12
We move all terms to the left:
5c+c-27-(3(c+4)-12)=0
We add all the numbers together, and all the variables
6c-(3(c+4)-12)-27=0
We calculate terms in parentheses: -(3(c+4)-12), so:We add all the numbers together, and all the variables
3(c+4)-12
We multiply parentheses
3c+12-12
We add all the numbers together, and all the variables
3c
Back to the equation:
-(3c)
3c-27=0
We move all terms containing c to the left, all other terms to the right
3c=27
c=27/3
c=9
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