5c(6c-5)=0

Solution for 5c(6c-5)=0 equation:

5c(6c-5)=0

We multiply parentheses

30c^2-25c=0

a = 30; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·30·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*30}=\frac{0}{60}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*30}=\frac{50}{60}
=5/6
$