5b-6+2b=3(b-2)+4b

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Solution for 5b-6+2b=3(b-2)+4b equation: 



5b-6+2b=3(b-2)+4b

We move all terms to the left:

5b-6+2b-(3(b-2)+4b)=0

We add all the numbers together, and all the variables

7b-(3(b-2)+4b)-6=0



We calculate terms in parentheses: -(3(b-2)+4b), so:

3(b-2)+4b

We add all the numbers together, and all the variables

4b+3(b-2)

We multiply parentheses

4b+3b-6

We add all the numbers together, and all the variables

7b-6

Back to the equation:

-(7b-6)



We get rid of parentheses

7b-7b+6-6=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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