5b-2(b+1)=6+b+2(b-4)

Solution for 5b-2(b+1)=6+b+2(b-4) equation:

Simplifying
5b + -2(b + 1) = 6 + b + 2(b + -4)

Reorder the terms:
5b + -2(1 + b) = 6 + b + 2(b + -4)
5b + (1 * -2 + b * -2) = 6 + b + 2(b + -4)
5b + (-2 + -2b) = 6 + b + 2(b + -4)

Reorder the terms:
-2 + 5b + -2b = 6 + b + 2(b + -4)

Combine like terms: 5b + -2b = 3b
-2 + 3b = 6 + b + 2(b + -4)

Reorder the terms:
-2 + 3b = 6 + b + 2(-4 + b)
-2 + 3b = 6 + b + (-4 * 2 + b * 2)
-2 + 3b = 6 + b + (-8 + 2b)

Reorder the terms:
-2 + 3b = 6 + -8 + b + 2b

Combine like terms: 6 + -8 = -2
-2 + 3b = -2 + b + 2b

Combine like terms: b + 2b = 3b
-2 + 3b = -2 + 3b

Add '2' to each side of the equation.
-2 + 2 + 3b = -2 + 2 + 3b

Combine like terms: -2 + 2 = 0
0 + 3b = -2 + 2 + 3b
3b = -2 + 2 + 3b

Combine like terms: -2 + 2 = 0
3b = 0 + 3b
3b = 3b

Add '-3b' to each side of the equation.
3b + -3b = 3b + -3b

Combine like terms: 3b + -3b = 0
0 = 3b + -3b

Combine like terms: 3b + -3b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.