5b+3b-1=(b+20)

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Solution for 5b+3b-1=(b+20) equation: 



5b+3b-1=(b+20)

We move all terms to the left:

5b+3b-1-((b+20))=0

We add all the numbers together, and all the variables

8b-((b+20))-1=0



We calculate terms in parentheses: -((b+20)), so:

(b+20)

We get rid of parentheses

b+20

Back to the equation:

-(b+20)



We get rid of parentheses

8b-b-20-1=0

We add all the numbers together, and all the variables

7b-21=0

We move all terms containing b to the left, all other terms to the right

7b=21

b=21/7

b=3

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