5b+32+2b=7(b+19)+3b

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Solution for 5b+32+2b=7(b+19)+3b equation: 



5b+32+2b=7(b+19)+3b

We move all terms to the left:

5b+32+2b-(7(b+19)+3b)=0

We add all the numbers together, and all the variables

7b-(7(b+19)+3b)+32=0



We calculate terms in parentheses: -(7(b+19)+3b), so:

7(b+19)+3b

We add all the numbers together, and all the variables

3b+7(b+19)

We multiply parentheses

3b+7b+133

We add all the numbers together, and all the variables

10b+133

Back to the equation:

-(10b+133)



We get rid of parentheses

7b-10b-133+32=0

We add all the numbers together, and all the variables

-3b-101=0

We move all terms containing b to the left, all other terms to the right

-3b=101

b=101/-3

b=-33+2/3

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