5a-4=3(a+1)+11a+4

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Solution for 5a-4=3(a+1)+11a+4 equation: 



5a-4=3(a+1)+11a+4

We move all terms to the left:

5a-4-(3(a+1)+11a+4)=0



We calculate terms in parentheses: -(3(a+1)+11a+4), so:

3(a+1)+11a+4

We add all the numbers together, and all the variables

11a+3(a+1)+4

We multiply parentheses

11a+3a+3+4

We add all the numbers together, and all the variables

14a+7

Back to the equation:

-(14a+7)



We get rid of parentheses

5a-14a-7-4=0

We add all the numbers together, and all the variables

-9a-11=0

We move all terms containing a to the left, all other terms to the right

-9a=11

a=11/-9

a=-1+2/9

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