5a-2(2a-7)+5=2(3a-1)+7+2(a+3)-9

Solution for 5a-2(2a-7)+5=2(3a-1)+7+2(a+3)-9 equation:

5a-2(2a-7)+5=2(3a-1)+7+2(a+3)-9

We move all terms to the left:

5a-2(2a-7)+5-(2(3a-1)+7+2(a+3)-9)=0

We multiply parentheses

5a-4a-(2(3a-1)+7+2(a+3)-9)+14+5=0


We calculate terms in parentheses: -(2(3a-1)+7+2(a+3)-9), so:

2(3a-1)+7+2(a+3)-9

determiningTheFunctionDomain
2(3a-1)+2(a+3)+7-9

We add all the numbers together, and all the variables

2(3a-1)+2(a+3)-2

We multiply parentheses

6a+2a-2+6-2

We add all the numbers together, and all the variables

8a+2

Back to the equation:

-(8a+2)


We add all the numbers together, and all the variables

a-(8a+2)+19=0

We get rid of parentheses

a-8a-2+19=0

We add all the numbers together, and all the variables

-7a+17=0

We move all terms containing a to the left, all other terms to the right

-7a=-17

a=-17/-7

a=2+3/7