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5=x+5/3x-1
We move all terms to the left:
5-(x+5/3x-1)=0
Domain of the equation: 3x-1)!=0We get rid of parentheses
x∈R
-x-5/3x+1+5=0
We multiply all the terms by the denominator
-x*3x+1*3x+5*3x-5=0
Wy multiply elements
-3x^2+3x+15x-5=0
We add all the numbers together, and all the variables
-3x^2+18x-5=0
a = -3; b = 18; c = -5;
Δ = b2-4ac
Δ = 182-4·(-3)·(-5)
Δ = 264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{264}=\sqrt{4*66}=\sqrt{4}*\sqrt{66}=2\sqrt{66}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{66}}{2*-3}=\frac{-18-2\sqrt{66}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{66}}{2*-3}=\frac{-18+2\sqrt{66}}{-6} $
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