5=j/3--4

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Solution for 5=j/3--4 equation: 


(1/2)*x^2-(6*ln(x-1))

-13 = f/3-15

-2/5-(-9/15) = 0

20*x^2-(68*x)+0*x^3+48 = 0

1;2;0;0;3;0

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