5=35/j

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Solution for 5=35/j equation: 



5=35/j

We move all terms to the left:

5-(35/j)=0



Domain of the equation: j)!=0

j!=0/1

j!=0

j∈R



We add all the numbers together, and all the variables

-(+35/j)+5=0

We get rid of parentheses

-35/j+5=0

We multiply all the terms by the denominator


5*j-35=0

We add all the numbers together, and all the variables

5j-35=0

We move all terms containing j to the left, all other terms to the right

5j=35

j=35/5

j=7

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