5=3/2(3)+b

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Solution for 5=3/2(3)+b equation: 



5=3/2(3)+b

We move all terms to the left:

5-(3/2(3)+b)=0



Domain of the equation: 23+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-23

b!=-23/1

b!=-23

b∈R



We add all the numbers together, and all the variables

-(+b+3/23)+5=0

We get rid of parentheses

-b+5-3/23=0

We multiply all the terms by the denominator


-b*23-3+5*23=0

We add all the numbers together, and all the variables

-b*23+112=0

Wy multiply elements

-23b+112=0

We move all terms containing b to the left, all other terms to the right

-23b=-112

b=-112/-23

b=4+20/23

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