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5=3+(2/2x+1)
We move all terms to the left:
5-(3+(2/2x+1))=0
Domain of the equation: 2x+1))!=0We multiply all the terms by the denominator
x∈R
-(3+(2+5*2x+1))=0
We calculate terms in parentheses: -(3+(2+5*2x+1)), so:We get rid of parentheses
3+(2+5*2x+1)
determiningTheFunctionDomain (2+5*2x+1)+3
We add all the numbers together, and all the variables
(5*2x+3)+3
We get rid of parentheses
5*2x+3+3
We add all the numbers together, and all the variables
5*2x+6
Wy multiply elements
10x+6
Back to the equation:
-(10x+6)
-10x-6=0
We move all terms containing x to the left, all other terms to the right
-10x=6
x=6/-10
x=-3/5
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