5=2/7(2x+28)

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Solution for 5=2/7(2x+28) equation: 



5=2/7(2x+28)

We move all terms to the left:

5-(2/7(2x+28))=0



Domain of the equation: 7(2x+28))!=0

x∈R



We multiply all the terms by the denominator


-(2+5*7(2x+28))=0



We calculate terms in parentheses: -(2+5*7(2x+28)), so:

2+5*7(2x+28)

determiningTheFunctionDomain
5*7(2x+28)+2

Wy multiply elements

35x(2+2

Back to the equation:

-(35x(2+2)



We add all the numbers together, and all the variables

-(35x4=0

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