5=2/(-2c)=-16

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Solution for 5=2/(-2c)=-16 equation: 



5=2/(-2c)=-16

We move all terms to the left:

5-(2/(-2c))=0



Domain of the equation: (-2c))!=0

c!=0/1

c!=0

c∈R



We multiply all the terms by the denominator


-(2+5*(-2c))=0



We calculate terms in parentheses: -(2+5*(-2c)), so:

2+5*(-2c)

determiningTheFunctionDomain
5*(-2c)+2

We multiply parentheses

-10c+2

Back to the equation:

-(-10c+2)



We get rid of parentheses

10c-2=0

We move all terms containing c to the left, all other terms to the right

10c=2

c=2/10

c=1/5

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