5=2(k-1)+3(2-k)

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Solution for 5=2(k-1)+3(2-k) equation: 



5=2(k-1)+3(2-k)

We move all terms to the left:

5-(2(k-1)+3(2-k))=0

We add all the numbers together, and all the variables

-(2(k-1)+3(-1k+2))+5=0



We calculate terms in parentheses: -(2(k-1)+3(-1k+2)), so:

2(k-1)+3(-1k+2)

We multiply parentheses

2k-3k-2+6

We add all the numbers together, and all the variables

-1k+4

Back to the equation:

-(-1k+4)



We get rid of parentheses

1k-4+5=0

We add all the numbers together, and all the variables

k+1=0

We move all terms containing k to the left, all other terms to the right

k=-1

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