5=2(2z-1)

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Solution for 5=2(2z-1) equation: 



5=2(2z-1)

We move all terms to the left:

5-(2(2z-1))=0



We calculate terms in parentheses: -(2(2z-1)), so:

2(2z-1)

We multiply parentheses

4z-2

Back to the equation:

-(4z-2)



We get rid of parentheses

-4z+2+5=0

We add all the numbers together, and all the variables

-4z+7=0

We move all terms containing z to the left, all other terms to the right

-4z=-7

z=-7/-4

z=1+3/4

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