5=15(1/3z-2)

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Solution for 5=15(1/3z-2) equation: 



5=15(1/3z-2)

We move all terms to the left:

5-(15(1/3z-2))=0



Domain of the equation: 3z-2))!=0

z∈R



We multiply all the terms by the denominator


-(15(1+5*3z-2))=0



We calculate terms in parentheses: -(15(1+5*3z-2)), so:

15(1+5*3z-2)

We add all the numbers together, and all the variables

15(5*3z-1)

We multiply parentheses

225z-15

Back to the equation:

-(225z-15)



We get rid of parentheses

-225z+15=0

We move all terms containing z to the left, all other terms to the right

-225z=-15

z=-15/-225

z=1/15

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