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5=1/3(-6x-9)
We move all terms to the left:
5-(1/3(-6x-9))=0
Domain of the equation: 3(-6x-9))!=0We multiply all the terms by the denominator
x∈R
-(1+5*3(-6x-9))=0
We calculate terms in parentheses: -(1+5*3(-6x-9)), so:
1+5*3(-6x-9)
determiningTheFunctionDomain 5*3(-6x-9)+1
Wy multiply elements
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We use the square of the difference formula
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Back to the equation:
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