5=1/2v+(-3)

Solution for 5=1/2v+(-3) equation:

5=1/2v+(-3)

We move all terms to the left:

5-(1/2v+(-3))=0


Domain of the equation: 2v+(-3))!=0

v∈R


We multiply all the terms by the denominator


-(1+5*2v+(-3))=0


We calculate terms in parentheses: -(1+5*2v+(-3)), so:

1+5*2v+(-3)

determiningTheFunctionDomain
5*2v+1+(-3)

We add all the numbers together, and all the variables

5*2v-2

Wy multiply elements

10v-2

Back to the equation:

-(10v-2)


We get rid of parentheses

-10v+2=0

We move all terms containing v to the left, all other terms to the right

-10v=-2

v=-2/-10

v=1/5