5=1/2(1+b2)2

Solution for 5=1/2(1+b2)2 equation:

5=1/2(1+b2)2

We move all terms to the left:

5-(1/2(1+b2)2)=0


Domain of the equation: 2(1+b2)2)!=0

b∈R


We add all the numbers together, and all the variables

-(1/2(+b^2+1)2)+5=0

We multiply all the terms by the denominator


-(1+5*2(+b^2+1)2)=0


We calculate terms in parentheses: -(1+5*2(+b^2+1)2), so:

1+5*2(+b^2+1)2

determiningTheFunctionDomain
5*2(+b^2+1)2+1

Wy multiply elements

10b(++1

We use the square of the difference formula

10b(+1

Back to the equation:

-(10b(+1)


We add all the numbers together, and all the variables

-(10b1=0