5=-8(y+3)-19

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Solution for 5=-8(y+3)-19 equation: 



5=-8(y+3)-19

We move all terms to the left:

5-(-8(y+3)-19)=0



We calculate terms in parentheses: -(-8(y+3)-19), so:

-8(y+3)-19

We multiply parentheses

-8y-24-19

We add all the numbers together, and all the variables

-8y-43

Back to the equation:

-(-8y-43)



We get rid of parentheses

8y+43+5=0

We add all the numbers together, and all the variables

8y+48=0

We move all terms containing y to the left, all other terms to the right

8y=-48

y=-48/8

y=-6

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