5=-2(3/10)+b

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Solution for 5=-2(3/10)+b equation: 



5=-2(3/10)+b

We move all terms to the left:

5-(-2(3/10)+b)=0



Domain of the equation: 10)+b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

-(-2(+3/10)+b)+5=0

We multiply all the terms by the denominator


-(-2(+3+5*10)+b)=0



We calculate terms in parentheses: -(-2(+3+5*10)+b), so:

-2(+3+5*10)+b

determiningTheFunctionDomain
b-2(+3+5*10)

We add all the numbers together, and all the variables

b-253

Back to the equation:

-(b-253)



We get rid of parentheses

-b+253=0

We add all the numbers together, and all the variables

-1b+253=0

We move all terms containing b to the left, all other terms to the right

-b=-253

b=-253/-1

b=+253

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