5=(3+c)/2

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Solution for 5=(3+c)/2 equation: 



5=(3+c)/2

We move all terms to the left:

5-((3+c)/2)=0

We add all the numbers together, and all the variables

-((c+3)/2)+5=0

We multiply all the terms by the denominator


-((c+3)+5*2)=0



We calculate terms in parentheses: -((c+3)+5*2), so:

(c+3)+5*2

We add all the numbers together, and all the variables

(c+3)+10

We get rid of parentheses

c+3+10

We add all the numbers together, and all the variables

c+13

Back to the equation:

-(c+13)



We get rid of parentheses

-c-13=0

We add all the numbers together, and all the variables

-1c-13=0

We move all terms containing c to the left, all other terms to the right

-c=13

c=13/-1

c=-13

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