59=1/2(x-21)

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Solution for 59=1/2(x-21) equation:



59=1/2(x-21)
We move all terms to the left:
59-(1/2(x-21))=0
Domain of the equation: 2(x-21))!=0
x∈R
We multiply all the terms by the denominator
-(1+59*2(x-21))=0
We calculate terms in parentheses: -(1+59*2(x-21)), so:
1+59*2(x-21)
determiningTheFunctionDomain 59*2(x-21)+1
Wy multiply elements
118x(x+1
Back to the equation:
-(118x(x+1)
We calculate terms in parentheses: -(118x(x+1), so:
118x(x+1
We calculate terms in parentheses: -(118x(x+1), so:
118x(x+1
We calculate terms in parentheses: -(118x(x+1), so:
118x(x+1
We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
118x(x+1
We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
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We calculate terms in parentheses: -(118x(x+1), so:
118x(x+1

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