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58=6x^2
We move all terms to the left:
58-(6x^2)=0
a = -6; b = 0; c = +58;
Δ = b2-4ac
Δ = 02-4·(-6)·58
Δ = 1392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1392}=\sqrt{16*87}=\sqrt{16}*\sqrt{87}=4\sqrt{87}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{87}}{2*-6}=\frac{0-4\sqrt{87}}{-12} =-\frac{4\sqrt{87}}{-12} =-\frac{\sqrt{87}}{-3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{87}}{2*-6}=\frac{0+4\sqrt{87}}{-12} =\frac{4\sqrt{87}}{-12} =\frac{\sqrt{87}}{-3} $
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