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58=2-5(2x-4)
We move all terms to the left:
58-(2-5(2x-4))=0
We calculate terms in parentheses: -(2-5(2x-4)), so:We get rid of parentheses
2-5(2x-4)
determiningTheFunctionDomain -5(2x-4)+2
We multiply parentheses
-10x+20+2
We add all the numbers together, and all the variables
-10x+22
Back to the equation:
-(-10x+22)
10x-22+58=0
We add all the numbers together, and all the variables
10x+36=0
We move all terms containing x to the left, all other terms to the right
10x=-36
x=-36/10
x=-3+3/5
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