58=2(1+4b)

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Solution for 58=2(1+4b) equation: 



58=2(1+4b)

We move all terms to the left:

58-(2(1+4b))=0

We add all the numbers together, and all the variables

-(2(4b+1))+58=0



We calculate terms in parentheses: -(2(4b+1)), so:

2(4b+1)

We multiply parentheses

8b+2

Back to the equation:

-(8b+2)



We get rid of parentheses

-8b-2+58=0

We add all the numbers together, and all the variables

-8b+56=0

We move all terms containing b to the left, all other terms to the right

-8b=-56

b=-56/-8

b=+7

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