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58=-2-5(2x-4)
We move all terms to the left:
58-(-2-5(2x-4))=0
We calculate terms in parentheses: -(-2-5(2x-4)), so:We get rid of parentheses
-2-5(2x-4)
determiningTheFunctionDomain -5(2x-4)-2
We multiply parentheses
-10x+20-2
We add all the numbers together, and all the variables
-10x+18
Back to the equation:
-(-10x+18)
10x-18+58=0
We add all the numbers together, and all the variables
10x+40=0
We move all terms containing x to the left, all other terms to the right
10x=-40
x=-40/10
x=-4
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