58=(a-12)+a

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Solution for 58=(a-12)+a equation: 



58=(a-12)+a

We move all terms to the left:

58-((a-12)+a)=0



We calculate terms in parentheses: -((a-12)+a), so:

(a-12)+a

We add all the numbers together, and all the variables

a+(a-12)

We get rid of parentheses

a+a-12

We add all the numbers together, and all the variables

2a-12

Back to the equation:

-(2a-12)



We get rid of parentheses

-2a+12+58=0

We add all the numbers together, and all the variables

-2a+70=0

We move all terms containing a to the left, all other terms to the right

-2a=-70

a=-70/-2

a=+35

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