58-2c-3=4c+20+c

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Solution for 58-2c-3=4c+20+c equation: 



58-2c-3=4c+20+c

We move all terms to the left:

58-2c-3-(4c+20+c)=0

We add all the numbers together, and all the variables

-2c-(5c+20)+58-3=0

We add all the numbers together, and all the variables

-2c-(5c+20)+55=0

We get rid of parentheses

-2c-5c-20+55=0

We add all the numbers together, and all the variables

-7c+35=0

We move all terms containing c to the left, all other terms to the right

-7c=-35

c=-35/-7

c=+5

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