58-(2c+3)=4(c+5)+6

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Solution for 58-(2c+3)=4(c+5)+6 equation: 



58-(2c+3)=4(c+5)+6

We move all terms to the left:

58-(2c+3)-(4(c+5)+6)=0

We get rid of parentheses

-2c-(4(c+5)+6)-3+58=0



We calculate terms in parentheses: -(4(c+5)+6), so:

4(c+5)+6

We multiply parentheses

4c+20+6

We add all the numbers together, and all the variables

4c+26

Back to the equation:

-(4c+26)



We add all the numbers together, and all the variables

-2c-(4c+26)+55=0

We get rid of parentheses

-2c-4c-26+55=0

We add all the numbers together, and all the variables

-6c+29=0

We move all terms containing c to the left, all other terms to the right

-6c=-29

c=-29/-6

c=4+5/6

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