57=5/9(f-32)

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Solution for 57=5/9(f-32) equation: 



57=5/9(f-32)

We move all terms to the left:

57-(5/9(f-32))=0



Domain of the equation: 9(f-32))!=0

f∈R



We multiply all the terms by the denominator


-(5+57*9(f-32))=0



We calculate terms in parentheses: -(5+57*9(f-32)), so:

5+57*9(f-32)

determiningTheFunctionDomain
57*9(f-32)+5

Wy multiply elements

513f(f+5

Back to the equation:

-(513f(f+5)





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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513f(f+5





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