57=2v-3(4v+)

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Solution for 57=2v-3(4v+) equation: 



57=2v-3(4v+)

We move all terms to the left:

57-(2v-3(4v+))=0

We add all the numbers together, and all the variables

-(2v-3(+4v))+57=0



We calculate terms in parentheses: -(2v-3(+4v)), so:

2v-3(+4v)

We multiply parentheses

2v-12v

We add all the numbers together, and all the variables

-10v

Back to the equation:

-(-10v)



We get rid of parentheses

10v+57=0

We move all terms containing v to the left, all other terms to the right

10v=-57

v=-57/10

v=-5+7/10

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