57+(2x)+(x=42)

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Solution for 57+(2x)+(x=42) equation: 



57+(2x)+(x=42)

We move all terms to the left:

57+(2x)+(x-(42))=0

We get rid of parentheses

2x+x-42+57=0

We add all the numbers together, and all the variables

3x+15=0

We move all terms containing x to the left, all other terms to the right

3x=-15

x=-15/3

x=-5

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