57(3)=7x(120/12)+33

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Solution for 57(3)=7x(120/12)+33 equation: 



57(3)=7x(120/12)+33

We move all terms to the left:

57(3)-(7x(120/12)+33)=0

We add all the numbers together, and all the variables

-(7x10+33)+573=0

We get rid of parentheses

-7x10-33+573=0

We add all the numbers together, and all the variables

-7x^10+540=0

We do not support expression: x^10

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