56=-16t2+60t

Solution for 56=-16t2+60t equation:

56=-16t^2+60t

We move all terms to the left:

56-(-16t^2+60t)=0

We get rid of parentheses

16t^2-60t+56=0

a = 16; b = -60; c = +56;
Δ = b2-4ac
Δ = -602-4·16·56
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4}{2*16}=\frac{56}{32}
=1+3/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4}{2*16}=\frac{64}{32}
=2
$