56-(3c+4)=4(c+7)=c

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Solution for 56-(3c+4)=4(c+7)=c equation: 



56-(3c+4)=4(c+7)=c

We move all terms to the left:

56-(3c+4)-(4(c+7))=0

We get rid of parentheses

-3c-(4(c+7))-4+56=0



We calculate terms in parentheses: -(4(c+7)), so:

4(c+7)

We multiply parentheses

4c+28

Back to the equation:

-(4c+28)



We add all the numbers together, and all the variables

-3c-(4c+28)+52=0

We get rid of parentheses

-3c-4c-28+52=0

We add all the numbers together, and all the variables

-7c+24=0

We move all terms containing c to the left, all other terms to the right

-7c=-24

c=-24/-7

c=3+3/7

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