56-(3c+4)=4(1c+7)+1c

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Solution for 56-(3c+4)=4(1c+7)+1c equation: 



56-(3c+4)=4(1c+7)+1c

We move all terms to the left:

56-(3c+4)-(4(1c+7)+1c)=0

We add all the numbers together, and all the variables

-(3c+4)-(4(c+7)+1c)+56=0

We get rid of parentheses

-3c-(4(c+7)+1c)-4+56=0



We calculate terms in parentheses: -(4(c+7)+1c), so:

4(c+7)+1c

We add all the numbers together, and all the variables

c+4(c+7)

We multiply parentheses

c+4c+28

We add all the numbers together, and all the variables

5c+28

Back to the equation:

-(5c+28)



We add all the numbers together, and all the variables

-3c-(5c+28)+52=0

We get rid of parentheses

-3c-5c-28+52=0

We add all the numbers together, and all the variables

-8c+24=0

We move all terms containing c to the left, all other terms to the right

-8c=-24

c=-24/-8

c=+3

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